What is the solution of the system of equations #c+3d=8# and #c=4 d-6#?

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Answer 1 · 2015-03-28T10:30:41

The answer is:

#c=2#
#d=2#.

Because:

#c+3d=8#
#c=4d-6#

Let's substitue #c# from the second equation to the first:

#4d-6+3d=8rArr7d=14rArrd=2#

and now let's go back:

#c=4*2-6=2#.