How do you write the point-slop form of an equation of the line that passes through the given point (5, -2) and has the given slope m=3?

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Answer 1 · 2015-04-01T22:25:57

The equation is #y=3x-17#

The general equation for a straight line is given by:

#y=mx+c#

Where #m# = gradient or slope.

#c=# intercept.

Putting in the values #rArr#

#-2=(3xx5)+c#

#c=-17#

So the equation of the line in question #rArr#

#y=3x-17#

I have assumed this is what your question was asking for.