How do you solve #14/(3x) = 6/(2x-5)#?

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Answer 1 · 2015-04-02T18:35:46

The answer is: #x=7#

First of all, #x !in {0, 5/2}#

Because those values will lead a "division by zero" error, which is a great sin in maths.

Now, we can get to work.

#3x * (14/(3x)) = 3x * (6/(2x-5))#

#14 = (18x)/(2x -5)#

#(2x-5) * 14 =(2x-5) * (18x)/(2x-5)#

#28x - 70 = 18x#
#10x = 70#
#x=7#

#x# is not #0# or #5/2# so this is a valid value.

The result is: #x=7#