Question

N has a mass of 26.19g H has a mass of 8.39g Cl has a mass of 65.42g mole for N is 26.19/14=1.87, mole for H is 8.39/1=8.39 mole for Cl is 65.42/35.5=1.84. Mole ratio for N is 1.87/1.84 is 1, H is 4.55 and for Cl is 1.What is the empirical formula?

Answer 1

The empirical formula would be

Mole ratios
N: = 1
H: = 4.55
Cl: = 1

Multiply mole ratios times 2.
N: = 1 x 2 = 2
H: = 4.55 x 2 = 9.1
Cl: = 1 x 2 = 2

Empirical Formula is `"N"_2"H"_9"Cl"_2"`.

I'm not sure that this is an actual compound. Your initial masses add up to 100, which is correct.