Question

Question #c44c2

Answer 1

`w = "-2 kJ"`

Start with the definitions.

`H = U + PV`, so

`ΔH = ΔU + Δ(PV)`

If the pressure is constant,

`ΔH = ΔU + PΔV`

But `w = -PΔV`, so

`ΔH = ΔU – w`

`w = ΔU – ΔH = "-2045 kJ – (-2043 kJ)" = "-2 kJ"`