Question

How to express `e^(2-i)` in the form `a + ib`?

Answer 1

I would write it as:
`e^2*e^(-1i)`
Then I will use the conversion from expoential to trigonometric form of a complex number as:
`re^(-itheta)=r[cos(theta)-isin(theta)]` with `theta=1` in radians;
and convert it into rectangular form getting:
`e^2[cos(1)-isin(1)]~=4-6i`