How do you differentiate $y = {cos}^{3} (3 x + 1)$ $y = cos^3(3x+1)$ ?

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How do you differentiate $y = {cos}^{3} (3 x + 1)$ $y = cos^3(3x+1)$ ?

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Answer 1 · 2015-04-07T21:36:16

I would use the Chain Rule deriving the ${()}^{3}$ $()^3$ first and then the $cos$ $cos$ and then the argument as:
$y'=3cos^2(3x+1)*[-sin(3x+1)]*3=-9cos^2(3x+1)sin(3x+1)$

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How do you differentiate $y = {cos}^{3} (3 x + 1)$ $y = cos^3(3x+1)$ ?

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How do you differentiate $y = {cos}^{3} (3 x + 1)$ $y = cos^3(3x+1)$ ?