Question

How do you find the limit of `sqrt(x^2- 3x)` as x approaches 3?

Answer 1

If `f(a)` exists then the
`lim_(xrarra) f(x) = f(a)`

For `f(x) = sqrt(x^2-3x)`

`f(3) = sqrt(0) = 0`

So
`lim_(xrarr3)sqrt(x^2-3x) = 0`