Question

How do you differentiate `y=sqrt(tan^-1x)`?

Answer 1

`dy/dx=1/(2sqrt(tan^-1x))(1/(1+x^2))`

`y=sqrt(tan^-1x)`

`dy/dx=1/2(tan^-1x)^((-1)/2)d/dxtan^-1x`

`dy/dx=1/(2sqrt(tan^-1x))(1/(1+x^2))`