How do you find the derivative of w^2 sec^2(3w)? Calculus Differentiating Trigonometric Functions Derivatives of y=sec(x), y=cot(x), y= csc(x) 1 Answer Anees Apr 16, 2015 Its derivative can be found by this way 2wsec^2(3w)+w^2. 2sec(3w)(sec3wtan3w)(3) 2wsec^2(3w)+6w^2sec^2(3w) tan3w Answer link Related questions What is Derivatives of y=sec(x) ? What is the Derivative of y=sec(x^2)? What is the Derivative of y=x sec(kx)? What is the Derivative of y=sec ^ 2(x)? What is the derivative of y=4 sec ^2(x)? What is the derivative of y=ln(sec(x)+tan(x))? What is the derivative of y=sec^2(x)? What is the derivative of y=sec^2(x) + tan^2(x)? What is the derivative of y=sec^3(x)? What is the derivative of y=sec(x) tan(x)? See all questions in Derivatives of y=sec(x), y=cot(x), y= csc(x) Impact of this question 2506 views around the world You can reuse this answer Creative Commons License