Using the double angle formula, how do you find the function values for #cos^2(pi/12) and sin^2(pi/8)#? Trigonometry Trigonometric Identities and Equations Double Angle Identities 1 Answer Nghi N. Apr 30, 2015 Use the trig identities: #cos 2a = 2.cos^2 a - 1# and #cos 2a = 1 - 2.sin^2 a#. #2.cos^2 (Pi/12) = 1 + cos (Pi/6) = 1 + (sqr3)/2 = 1.866.# #cos^2 (Pi/12) = 1.866/2 = 0.933 # #2.sin^2 (Pi/8) = 1 - cos (Pi/4) = 1 - (sqr2)/2 = 0.293# #sin^2 (Pi/8) = 0.147.# Answer link Related questions What are Double Angle Identities? How do you use a double angle identity to find the exact value of each expression? How do you use a double-angle identity to find the exact value of sin 120°? How do you use double angle identities to solve equations? How do you find all solutions for #sin 2x = cos x# for the interval #[0,2pi]#? How do you find all solutions for #4sinthetacostheta=sqrt(3)# for the interval #[0,2pi]#? How do you simplify #cosx(2sinx + cosx)-sin^2x#? If #tan x = 0.3#, then how do you find tan 2x? If #sin x= 5/3#, what is the sin 2x equal to? How do you prove #cos2A = 2cos^2 A - 1#? See all questions in Double Angle Identities Impact of this question 3859 views around the world You can reuse this answer Creative Commons License