How do you solve abs(8x) > 20? Algebra Linear Inequalities and Absolute Value Absolute Value Inequalities 1 Answer Alberto M. May 3, 2015 The answer is x>5/2 or x<-5/2 abs(8x)=8abs(x) => abs(8x)>20 <=> 8abs(x)>20 <=> abs(x)>5/2 <=> x>5/2 or x<-5/2 Answer link Related questions How do you solve absolute value inequalities? When is a solution "all real numbers" when solving absolute value inequalities? How do you solve |a+1|\le 4? How do you solve |-6t+3|+9 \ge 18? How do you graph |7x| \ge 21? Are all absolute value inequalities going to turn into compound inequalities? How do you solve for x given |\frac{2x}{7}+9 | > frac{5}{7}? How do you solve abs(2x-3)<=4? How do you solve abs(2-x)>abs(x+1)? How do you solve this absolute-value inequality 6abs(2x + 5 )> 66? See all questions in Absolute Value Inequalities Impact of this question 1571 views around the world You can reuse this answer Creative Commons License