Question

What is the derivative of `sin^2 (2x+3)`?

Answer 1

Here you can distinguish three functions:
`()^2` then `sin` and finally `2x+3`;
we can use the Chain Rule to "open" the derivative of this function deriving each one as it is and multiply together:

`y'=2[sin^(2-1)(2x+3)]cos(2x+3)*(2)=`
`=4sin(2x+3)cos(2x+3)=`