Question

Question #333cc

Answer 1

`"I"` pick 4/Copper(II) Carbonate (`"CuCO"_3`)

The gas is probably `"CO"_2(g)`

`"CuCO"_3(s) + 2"HCl"(aq) rarr "CuCl"_2(aq) + "H"_2"O"(l) + "CO"_2(g)`