How do you solve a^2-sqrt(3)a+1 = 0a2−√3a+1=0 ?
2 Answers
So we have:
Subtracting 1/4 from both sides, we get:
This has no real number solutions since the square of any real number is non-negative.
If you want complex solutions,
Adding
I would start applying the formula to solve quadratic equations (in fact, this is a quadratic equation in "a"):
As you can see, the equation has no real solution, since it has a square root of a negative number (
-
So, if you are working with real numbers, the answer is that there is no
a in RR which makesa^2-sqrt3a+1 = 0 . -
But if you are working with complex numbers, then there are two solutions:
a_1=(sqrt3+i)/2 anda_2=(sqrt3-i)/2 .