Question

How do you rationalize `(sqrt3-sqrt2)/ ( sqrt3+sqrt2)`?

Answer 1

You can multiply and divide by: `sqrt(3)-sqrt(2)` to get:
`(sqrt(3)-sqrt(2))/(sqrt(3)+sqrt(2))*(sqrt(3)-sqrt(2))/(sqrt(3)-sqrt(2))=`
`=(sqrt(3)-sqrt(2))^2/(3-2)=3-2sqrt(6)+2=5-2sqrt(6)`