Question

Human body temperatures are normally distributed with a mean of 98.20 and a standard deviation of 0.62, how do you find the z-score corresponding to a body temperature of 97.93?

Answer 1

All you need to do is take a look at your formula for the z-score, which is :

`z= (barx - mu)/sigma`

where `barx` is your tested mean

`barx = 97.93`

and `mu` is the total mean

`mu = 98.2`

and `sigma` is the standard deviation

`sigma= 0.62`

so now to find the z-score we just put all our info into the formula.

`z = (97.93 - 98.2)/0.62`

thus `z ~~ -0.4355`