How do you solve the system #x+5y=2# and #x-1=2y#?

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Answer 1 · 2015-05-19T14:30:14

You can isolate one variable in one equation and, then, substitute its value in the other equation:

Let's isolate #x# in the first equation, for example.

#x=2-5y#

Now, substituting it:

#(2-5y)-1=2y#
#1=7y#
#y=1/7#

Now, as we know #x=2-5y# and #y=1/7#,

#x=2-5(1/7)#
#x=2-5/7#
#x=9/7#