Question #635c0

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il maestro
May 20, 2015

pH =4.56
The partial neutralization of acetic acid by sodium hydroxide leaves 0.0015 moles of acid and produces 0.001 moles of acetate.
The final solution is a buffer of acetic acid and acetate.
Final concentration of acetic acid (#AcOH#) =#0.1 M *15/35#
=0.0428 M
Final concentration of #(OH^-)# = acetateion(#AcO^-#)=#0.1M*10/35#=0.0286 M
From the Henderson-Hasselbach equation:
#pH=pKa+log ((Ac^-)/(HAc))#
pH=#-log1.8*10^-5# + # log (0.0287/0.0428)# = 4.74-0.17 = 4.56

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