Question

The sum of 4 consecutive even integers is 132, what are the integers?

Answer 1

Suppose the integers are `n`, `n + 2`, `n + 4` and `n + 6`.

`132 = n + (n+2) + (n+4) + (n+6) = 4n+12`

Subtract `12` from both sides to get:

`4n = 120`

Divide both sides by `4` to get:

`n=30`

So the numbers are:

`30, 32, 34, 36`.