How do you solve the system #−3x + y = 2# and #4x + 2y = 4#? Algebra Systems of Equations and Inequalities Systems Using Substitution 1 Answer Elvan Burcu K. May 29, 2015 #-3x + y =3 => y = 3 +3x # ; #4x + 2y = 4 => 4x + 2*(3+3x)= 4 => 4x+6+6x=4 # # => 10x +6 =4 => 10x =-2 => x=-2/10=-1/5 # #y=3+3x => y=3+3*(-1/5) => y= 3-3/5 => y= 15/5 - 3/5 # # y= 12/5 # Answer link Related questions How do you solve systems of equations using the substitution method? How do you check your solutions to a systems of equations using the substitution method? When is the substitution method easier to use? How do you know if a solution is "no solution" or "infinite" when using the substitution method? How do you solve #y=-6x-3# and #y=3# using the substitution method? How do you solve #12y-3x=-1# and #x-4y=1# using the substitution method? Which method do you use to solve the system of equations #y=1/4x-14# and #y=19/8x+7#? What are the 2 numbers if the sum is 70 and they differ by 11? How do you solve #x+y=5# and #3x+y=15# using the substitution method? What is the point of intersection of the lines #x+2y=4# and #-x-3y=-7#? See all questions in Systems Using Substitution Impact of this question 2001 views around the world You can reuse this answer Creative Commons License