Question

Question #a6130

Answer 1

The half life is 6.86s.

For a 2nd order reaction the half life depends on the initial concentration:

`t_((1)/(2))=(1)/(k[A_0])`

So:

`t_((1)/(2))=(1)/((0.54xx0.27))`

`t_((1)/(2))=6.86"s"`