How do you write #y= -(4/5)x + (6/5)# in standard form?

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Answer 1 · 2015-05-30T11:00:49

Standard form of a line:

#Ax+By=C#

#y=-(4/5)x+(6/5)#

Multiply both sides by #5#:

#5y=-4x+6#

Rearrange:

#color(green)[4x+5y=6#