Question

The sum of three consecutive even integers is 168, what are the integers?

Answer 1

If the integers are `n-2`, `n` and `n+2`, then

`168 = (n-2) + n + (n+2) = 3n`

Divide both ends by `3` to get:

`n = 56`

So the three consecutive even integers are `54`, `56` and `58`,