Question

What is the conjugate of the square root of 2 + the square root of 3 + the square root of 5?

Answer 1

`sqrt(2)+sqrt(3)+sqrt(5)` does not have one conjugate. If you are trying to eliminate it from a denominator, then you need to multiply by something like:

`(sqrt(2)+sqrt(3)-sqrt(5))(sqrt(2)-sqrt(3)+sqrt(5))(sqrt(2)-sqrt(3)-sqrt(5))`

The product of `(sqrt(2)+sqrt(3)+sqrt(5))` and this is `-24`