How do you solve #abs(2x-5)> -1#?

1 Answer
Alan P.
Jun 2, 2015

Given #abs(2x-5) > -1#

We first note that by definition:
#color(white)("XXXXX")##abs( "anything") >= 0#
Therefore
#color(white)("XXXXX")##abs(2x-5)> -1# is valid for any value of #x#

The "solution" is
#color(white)("XXXXX")# All #x epsilon RR# (or, actually, all #x epsilon CC# if you want to expand to complex numbers).

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