How do you solve #abs(2x-5)> -1#?

1 Answer
Alan P.
Jun 2, 2015

Given #abs(2x-5) > -1#

We first note that by definition:
#color(white)("XXXXX")##abs( "anything") >= 0#
Therefore
#color(white)("XXXXX")##abs(2x-5)> -1# is valid for any value of #x#

The "solution" is
#color(white)("XXXXX")# All #x epsilon RR# (or, actually, all #x epsilon CC# if you want to expand to complex numbers).

Related questions
See all questions in Absolute Value Inequalities
Impact of this question
1454 views around the world
You can reuse this answer
Creative Commons License