How do you graph # f(x) = 2abs x+1 #? Algebra Linear Inequalities and Absolute Value Absolute Value Inequalities 1 Answer George C. Jun 4, 2015 When #x >= 0# we have #f(x) = 2abs(x) + 1 = 2x+1#, which is a straight line of slope #2#, starting from #(0, 1)# When #x <= 0# we have #f(x) = 2abs(x)+1 = -2x+1#, which is a straight line of slope #-2#, ending at #(0, 1)# So #f(x)# is basically a 'V' shape of slope #+-2# with vertex at #(0, 1)# graph{abs(2x)+1 [-10.04, 9.96, -2.24, 7.76]} Answer link Related questions How do you solve absolute value inequalities? When is a solution "all real numbers" when solving absolute value inequalities? How do you solve #|a+1|\le 4#? How do you solve #|-6t+3|+9 \ge 18#? How do you graph #|7x| \ge 21#? Are all absolute value inequalities going to turn into compound inequalities? How do you solve for x given #|\frac{2x}{7}+9 | > frac{5}{7}#? How do you solve #abs(2x-3)<=4#? How do you solve #abs(2-x)>abs(x+1)#? How do you solve this absolute-value inequality #6abs(2x + 5 )> 66#? See all questions in Absolute Value Inequalities Impact of this question 1540 views around the world You can reuse this answer Creative Commons License