How do you solve by substitution $2 x = 3 y$ $2x=3y$ and $x = 3 y - 3$ $x=3y-3$ ?

Question

5819 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-06-05T14:26:26

$x = 3$ $x = 3$
$y = 2$ $y = 2$

First, substitute $3 y$ $3y$ in the second equation with $2 x$ $2x$ (this is given to us in the first equation), and solve for x:

$x = 2 x - 3$ $x = 2x -3$
$x = 3$ $x= 3$

Insert x's value back into first equation, and solve for y:

$2 \cdot 3 = 3 \cdot y$ $2 * 3 = 3*y$
$y = 2$ $y = 2$

Solution is: $x = 3, y = 2$ $x = 3, y = 2$

How do you solve by substitution 2x=3y2x=3y2x=3y and x=3y-3x=3y−3x=3y-3?