How do you evaluate #log 1#?

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Answer 1 · 2015-06-11T18:37:02

#log1=0#

You. basically. want to find the number #a# that used as exponent of the base #b# of your log gives #1#:
#log_b1=a#
i.e.:
#b^a=1#
#b^0=1#

#a=0#
because a number to the power zero gives you #1#.

Answer 2 · 2015-06-11T18:37:29

#log_10 1# can be evaluated like so:

#log 1 = x#

#10^(log_10 1) = 10^x#

10 raised to a log base 10 of something is that something.

#1 = 10^x#

Anything raised to the 0 is 1.

#x = 0#

Thus, #log 1 = 0#.