Question #bbf99

1 Answer
Olivier B.
Jun 12, 2015

The horizontal component is #7.4m*s^(-2)#
The vertical component is #2.1m*s^(-2)#

Explanation:

The problem is described by the image below:

enter image source here

We have a right triangle. Its hypothenuse is the acceleration of #7.7m*s^(-2)#, its horizontal component is the side named X and its vertical component is the side named Y.

Trigonometry tells us that
#cos(16°)=X/7.7 rarr X = 7.7cos(16°) ~~ 7.4m*s^(-2)#
#sin(16°)=Y/7.7 rarr Y = 7.7sin(16°) ~~ 2.1m*s^(-2)#

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