How do you find the derivative for $f(x) = (2x+1)(4-x^2)(1+x^2)$ ?

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Answer 1 · 2015-06-14T19:16:38

$y'=2(-5x^4-2x^3+9x^2-3x+4)$ .

in this way:

$y'=2*(4-x^2)(1+x^2)+(2x+1)* (-2x)*(1+x^2)+(2x+1)(4-x^2)*2x=$

$=2(4+4x^2-x^2-x^4-2x^2-2x^4-x-x^3+8x^2-2x^4+4x-x^3)=$

$=2(-5x^4-2x^3+9x^2-3x+4)$ .

How do you find the derivative for f(x) = (2x+1)(4-x^2)(1+x^2)f(x) = (2x+1)(4-x^2)(1+x^2)?