Question

How do you solve `abs(2x + 1) > -3`?

Answer 1

This is satisfied for all `x in RR` since `abs(y) >= 0` for all `y in RR`.

Explanation:

For all `x in RR` the expression `2x + 1` is well defined and `abs(2x+1) >= 0 > -3`

In interval notation the solution is `x in (-oo, oo)`