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Given: $f (x) = 2 + \sqrt{- 3 x + 1}$ $f(x) = 2+ sqrt(-3x+1)$ , $q (x) = \frac{5 x}{x + 2}$ $q(x) = (5x)/(x+2)$ , and $m (x) = ∣ ∣ 7 - x^{2} ∣ ∣ + x$ $m(x) = abs(7 - x^2) + x$ , how do you find f(-5)?

1 Answer

Jun 18, 2015

$f (- 5) = 2 + \sqrt{- 3 (- 5) + 1} = 2 + \sqrt{16} = 6$ $f(-5)=2+sqrt(-3(-5)+1) = 2+sqrt(16) =6$

Explanation:

The only relevant function definition among those included in the question is
$XXXX$ $color(white)("XXXX")$ $f (x) = 2 + \sqrt{- 3 x + 1}$ $f(x) = 2 +sqrt(-3x+1)$

To evaluate $f (- 5)$ $f(-5)$
simply replace the $x$ $x$ in the function definition with $(- 5)$ $(-5)$ as shown and perform the arithmetic operations.

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