How do you simplify $\sqrt{18} + \sqrt{2}$ $sqrt18+sqrt2$ ?

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How do you simplify $\sqrt{18} + \sqrt{2}$ $sqrt18+sqrt2$ ?

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Answer 1 · 2015-07-01T22:27:05

$\sqrt{18} + \sqrt{2} = 4 \sqrt{2}$ $sqrt(18)+sqrt(2) = 4sqrt(2)$

Explanation:

If $a \geq 0$ $a >= 0$ then $\sqrt{a^{2}} = a$ $sqrt(a^2) = a$

If $a, b \geq 0$ $a, b >= 0$ then $\sqrt{a b} = \sqrt{a} \sqrt{b}$ $sqrt(ab) = sqrt(a)sqrt(b)$

$\sqrt{18} + \sqrt{2}$ $sqrt(18)+sqrt(2)$

$= \sqrt{3^{2} \cdot 2} + \sqrt{2}$ $=sqrt(3^2*2) + sqrt(2)$

$= \sqrt{3^{2}} \cdot \sqrt{2} + \sqrt{2}$ $=sqrt(3^2)*sqrt(2) + sqrt(2)$

$= 3 \sqrt{2} + \sqrt{2}$ $=3sqrt(2)+sqrt(2)$

$= (3 + 1) \sqrt{2}$ $=(3+1)sqrt(2)$

$= 4 \sqrt{2}$ $=4sqrt(2)$

Answer 2 · 2015-07-01T22:28:47

I found: $4 \sqrt{2}$ $4sqrt(2)$

Explanation:

Você pode escrever a primeira raiz como $\sqrt{9 \cdot 2}$ $sqrt(9*2)$ e tirar fora da raiz $9$ $9$ que vira $3$ $3$ :
Assim:
$\sqrt{18} + \sqrt{2} = \sqrt{9 \cdot 2} + \sqrt{2} =$ $sqrt(18)+sqrt(2)=sqrt(9*2)+sqrt(2)=$
$= 3 \sqrt{2} + \sqrt{2} =$ $=3sqrt(2)+sqrt(2)=$ agora pode somar os termos parecidos e ter:
$= 4 \sqrt{2}$ $=4sqrt(2)$

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How do you simplify $\sqrt{18} + \sqrt{2}$ $sqrt18+sqrt2$ ?

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