Question

Question #fe2cf

Answer 1

The equation of motion in this case is:
`s=vt+10`

Explanation:

If I got it correctly you have the following:

The equation of motion should be `s=vt` where `s` is the distance and `v` is the velocity (no acceleration involved); but here you have to consider the initial position not at zero but at `10m` (when you start your stopwatch the car is at the `10m` mark!)) so you get:
`color(red)(s=vt+10)`

At `t=0` your car is already at `s(0)=10m` while at `t=8s` your car is at `s(8)=vt+10=5*8+10=50m`.

Hope it is not confusing!