Is the sequence 3, 12, 36, ... a geometric sequence?

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Answer 1 · 2015-07-02T16:01:28

Here, $r_{1} \neq r_{2}$ $r_1 != r_2$ , hence the sequence is not geometric.

The sequence given is $3, 12, 36$ $3, 12, 36$

In a geometric sequence, a constant common ratio $r$ $r$ is maintained all through out the sequence.

The common ratio, $r$ $r$ is obtained by dividing a term by its preceding term

Finding $r$ $r$

1) $r_{1} = \frac{12}{3} = 4$ $r_1 = 12/3= 4$

2) $r_{2} = \frac{36}{12} = 3$ $r_2 = 36/12 = 3$

Since $r_{1} \neq r_{2}$ $r_1 != r_2$ the sequence is not geometric.