Question

How do you use properties of logarithms to write `ln(2/3)` in terms of a and b if `ln2 = a` and `ln3 = b`?

Answer 1

`ln(2/3) = a - b`

Explanation:

Property: `ln(x/y) = lnx -lny`

So

`ln(2/3) = ln(2) – ln3`

Let `ln2 = a` and `ln3 = b`.

Then

`ln(2/3) = a – b`