A transition of an electron between two different energy levels produced a series of line spectrum . calculate the wavelength of (β) line in Paschen series. wavelength in nanometer?

1 Answer
Jul 6, 2015

I found: #lambda=1282 nm#

Explanation:

Considering your #beta# line in the Paschen series as a transition from n = 5 to n = 3:
http://www.daviddarling.info/encyclopedia/L/Lyman_series.html
I would use Rydberg Formula:
#1/lambda=R(1/n_(low)^2-1/n_(up)^2)#
Where:
#lambda# is the wavelength;
#R# is Reydberg Constant (#=1.097373xx10^7 m^-1#);
#n_(low) and n_(up)# are the two quantum numbers caracterizing the transition.
so you get:
#1/lambda=1.097373xx10^7(1/3^2-1/5^2)=7.8xx10^5m^-1#
#lambda=1282 nm#