Question #1fec9

Question

2039 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-07-10T18:43:18

enter image source here

In order to obtain the various values of #y#, we have to put each value of #x# in the equation #y=x^2-2x-1#

Here we go:

#x=-2#
We have, #y=(-2)^2-2xx(-2)-1=4+4-1=7#

#x=-1#
We have, #y=(-1)^2-2xx(-1)-1=1+2-1=2#

#x=0#
We have, #y=(0)^2-2xx(0)-1=0+0-1=-1#

#x=1#
We have, #y=(1)^2-2xx(1)-1=1-2-1=-2#

#x=2#
We have, #y=(2)^2-2xx(2)-1=4-4-1=-1#

#x=3#
We have, #y=(3)^2-2xx(3)-1=9-6-1=2#

#x=4#
We have, #y=(4)^2-2xx(4)-1=16-8-1=7#