Question

Question #e1fc4

Answer 1

`dy/dx=(2ln2)4^sec(x)sec(x)tan(x)`

Explanation:

Lets say we want to find the derivative of `2^x`.
It is `(ln2)2^x`

In the problem we do the same thing and remember
to use the chain rule.

`dy/dx=(ln4)4^sec(x)d/dx[sec(x)]`

`dy/dx=(ln2^2)4^sec(x)sec(x)tan(x)`

`dy/dx=(2ln2)4^sec(x)sec(x)tan(x)`