Question

Question #8dc30

Answer 1

The Euler Formula and the trigonometric form of a complex number perhaps?

Explanation:

Well, I am not sure about possible implications apart for the Euler Formula:
`re^(itheta)=r(cos(theta)+isin(theta))`
where on the right you have the trigonometric form of a complex number.

In your case you have:
`r=1`
`theta=pi`

so you get:

`e^(pii)=1(cos(pi)+isin(pi))=1(-1+0)=-1`