How do you simplify: the square root of 24x times the square root of 6x?

1 Answer
Jul 28, 2015

Your problem stated:

#sqrt(24x)sqrt(6x)#

which already implies the positive domain of #x#.

You can combine the square roots to get:

#= sqrt(24x*6x)#

Multiply stuff in the square root:
#= sqrt(24*6*x^2)#

Pull #x^2# out by reversing the first step, basically, and evaluating the result:
#= sqrt(24*6)x#
(this is OK without absolute values because the original problem had only positive #sqrtx#.)

#=sqrt(144)x#

#= color(blue)(12x)#