Question

What is the derivative of `sin(ax)`?

Answer 1

`acos(ax)`

Explanation:

We know `d/dx(sin(x))=cos(x)` and `d/dx(f(g(x))=f'(g(x))*g'(x)` (the Chain Rule).

Use these two rules now, with `f(x)=sin(x)` and `g(x)=a x` (where `a` is a constant).