Question

How do you find the volume of the region bounded by `y = (x)^(1/2)`; `y=0` and `x = 4` rotated about the x-axis?

Answer 1

`8 pi`

Explanation:

`y = x^(1/2)`
`V = pi int_0^4y^2dx = pi/2[x^2]_0^4 = 8pi`