Question #c9838

2 Answers
Aug 14, 2015

Have a look:

Explanation:

I used the Quadratic Formula to solve your equation:
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Aug 14, 2015

#z^2 + az + b = 0#

If #z_1# and #z_2# are solutions, then:
# (z - z_1)(z - z_2) = 0 #
# z^2 - (z_1 + z_2)z +z_1z_2 = 0 #

Equation coefficients:
#z_1z_2 = b#
# z_1 + z_2 = -a #