How do you solve using this equation (#2x^2 = 40#) using the square root property?

1 Answer
Aug 17, 2015

We first divide both sides by #2# to get #x^2=20#

Explanation:

Then we take the square root at both sides, but remember that both

#sqrt20and -sqrt20# give #20# when squared.

So #x_(1,2)=+-sqrt20=+-2sqrt5# (two answers)