What is the 32nd term of the arithmetic sequence where a1 = 4 and a6 = 24 ?

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Answer 1 · 2015-08-27T08:18:18

#color(blue)(a_32= 128#

The data given is :
#a_1=4#
#a_6=24#

The formula for #nth# term is:
#color(blue)(a_n = a_1+(n-1)d#

Applying the same:
#a_6 = a_1+(6-1) *d #

#24=4+ 5 d#

#5 d = 20#

#color(blue)(d=4#

Now,
#a_32=a_1+(32-1) *d#

#=4 + 31(4)#

#= 4+124#

#color(blue)(a_32= 128#