Question

How do you find the derivative of `cos^2(x^3)`?

Answer 1

`f'(x)=-6x^(2).cos(x^(3)).sin(x^(3))`

Explanation:

`f(x)=cos^2(x^3)`

Apply the chain rule:

`f'(x)=-2cos(x^3).sin(x^3).3x^2`

`f'(x)=-6x^(2).cos(x^3).sin(x^3)`