Question

How do you simplify `Log_(2)(10)`?

Answer 1

`log_2(10) = 1/log(2)`

Explanation:

Use the change of base formula: `log_a(b) = log_c(b)/log_a(b)`

`log_2(10) = log_10(10)/log_10(2) = 1/log(2)`

since `log_10 = log`

In general, `log_a(b) = log_b(b)/log_b(a) = 1/log_b(a)`