How do you find the domain and range of #y = log (x - 2) + 1#? Precalculus Functions Defined and Notation Domain 1 Answer Ernest Z. Sep 2, 2015 See below. Explanation: #y = log(x-2)+1# The logarithm of zero or a negative number is undefined, so #x# must be greater than #2#. The domain is #x>2#. The value of a logarithm can be any real number, so the range is all real numbers. Answer link Related questions What is the domain of a function? What are common mistakes students make when working with domain? How does the domain of a function relate to its x-values? What is the domain of a linear function? What is the domain of a quadratic function? What is the domain of a function like #f(x) = 5x^2#? What is the domain of #f(x) = {(1, 2), (3, 4), (5, 6), (7, 8), (9, 10), (10, 10)}#? What is the domain of #f(x) = x#? How do I find the domain of the function #f(x) = 2x#? How do I find the domain of the function #f(x)=5x^2+2x-1#? See all questions in Domain Impact of this question 7295 views around the world You can reuse this answer Creative Commons License